X=4,x^2+3=

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Solution for X=4,x^2+3= equation: 



X=4.X^2+3=

We move all terms to the left:

X-(4.X^2+3)=0

We get rid of parentheses

-4.X^2+X-3=0

We add all the numbers together, and all the variables

-4X^2+X-3=0

a = -4; b = 1; c = -3;
Δ = b2-4ac
Δ = 12-4·(-4)·(-3)
Δ = -47
Delta is less than zero, so there is no solution for the equation

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